Nuprl Lemma : do-apply-p-co-filter
11,40
postcript
pdf
T
:Type,
P
:(
T
),
f
:(
x
:
T
. Dec(
P
(
x
))),
x
:
T
.
(
can-apply(p-co-filter(
f
);
x
))
(do-apply(p-co-filter(
f
);
x
) =
x
)
latex
ProofTree
Definitions
b
,
do-apply(
f
;
x
)
,
p-co-filter(
f
)
,
can-apply(
f
;
x
)
,
x
:
A
B
(
x
)
,
s
=
t
,
P
Q
,
x
:
A
.
B
(
x
)
,
f
(
a
)
,
x
(
s
)
,
Dec(
P
)
,
Type
,
,
True
,
False
,
left
+
right
,
P
Q
,
t
T
origin